Tarea 3

SONIA ISELA GARCIA RAMIREZ JAB SAB A.

1)   FORMULA                                SUSTITUCION

      Pe = P/V                                    VPe = P

P=? 0.486 Ton                                1m3 -------1,000,000cm3

V=o.18M3=180,000cm3            0.18m3-----X

Pe=2.70g/cm3                               x=180,000cm3

1kg-------1,000g                           1Ton---------1,000kg

X   --------486,000g                      x     ----------486kg

X=486kg                                       x=0.486Ton

P=(180,000)(2.70)=486,000g

2)   FORMULA

      Ph=Sgh         Ph= (1,025)(9.8)(20)=184,500N/m2

      Ph=? 184,500N/m2 

      S= 1,025Kg/m3

      H= 20m

      G= 9.8m/S2

                       

      Ph=Sgh         Ph= (1.000)(3790)(9.8) = 37,142,000N/M2

      S= 1,000Kg/m3

      G= 9.8m/S2

       H= 3,790m

3)  LA PRESION ES LA MISMA EN AMBOS CASOS.

       1Kgf= 9.8N X 6 = 58.8N                     R=29,400N

       1Kgf= 9.8N X 90 = 882N                    R = 29,400N

      

       FORMULA                                                      FORMULA

       P=F/A       1 m2 -------- 1000cm2                 P = F/A          1 m2 ------1,000cm2

                          X  ----------- 2cm2                                                  X  --------30cm2

                          X=0.002m2                                                            X = 0.03m2

       F = 58.8 N          P = 58.8/0.002                     F=882N            P = 882/0.03m2

       A = 2cm2            P = 29,400N                         A = 30cm2       P = 29,400N

 

4) FORMULA                                 SUSTITUCION

     FI/A1 =F2/A2                          (A2)FI/A1=F2     A1F2=A2F1          A2=F2/F1(A1)

     A2=F2/F1(A1)                         950 X 4 = 3,800N

    F1= 950N                                   

    A1= 5cm = 0.05m                     1m -------- 100cm

    F2= 3800N                                  X --------- 5cm                    

    A2= ? 0.2m                                A2 =3,800/950(0.05)=(4)(0.05) = 0.2m

 

5)    

         32 – 10 = 22°C                                       R1= 22°C

          K = 22 + 273 = 295K                             R2= 295K

          °F = 9/5(22) + 32 = 71.6°F                  R3=71.6°F